LongHW6Solution - Long Answer Homework 6 Acceleration...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Long Answer Homework 6 Acceleration Solution(Chapter 4) Assignment Due: Tuesday May 26, 2009 6.1) During a study break, you toss a baseball straight up. Upon watching the ball’s flight, you  begin to wonder about the motion of the ball while it is in the air.  a) What is the ball’s acceleration  after  leaving your hand (while on its way up)? b) What is the acceleration of the ball at the peak of its flight? c) What is the acceleration of the ball on its way down? d) What is the ball’s velocity at the peak? 6.2) A batter hits a baseball which rises vertically from chest height (1.2m) to 30m. How much  time elapses from the instant the ball is hit until it strikes the ground? Aim your x-axis upward  and set the ground level to be the origin of your coordinate system. Solution: With the ground x=0, and implies that upward x is positive, then acceleration is –g. This is only one method to find the  time it takes for the ball to hit the ground. Use the kinematic equation: xf=xi+vi*t+1/2*a*t^2 For going up, we have xi=1.2m (ball leaves the bat at chest height), xf=0m (hit the ground), vi=?, a=-g, t=?. So 0m =  1.2m +vi*t – ½*9.8m/s^2*t^2.  But we have two unknowns, vi, and t. To find the initial velocity that the ball leaves the  bat, we can use
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 06/04/2009 for the course PHYS 2054 taught by Professor Stewart during the Spring '08 term at Arkansas.

Page1 / 7

LongHW6Solution - Long Answer Homework 6 Acceleration...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online