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Unformatted text preview: ) P ( E  F ). We Frst calculate P ( E  F ). We are therefore given that after 9 draws, three hearts have been found. Thus, 6 nonhearts have been found. There are 529 = 43 cards remaining, of which 13  3 = 10 are hearts. Thus, P ( E  F ) = 10 / 43. To calculate P ( F ) we need to count possibilities by considering draws as permutations of the 52 cards. Note that the number of permutations of 9 objects from 52 is exactly 52 P 9 = 52! / 43!. The number of ways to choose 3 hearts and 6 nonhearts is exactly ( 13 3 )( 39 6 ) However, for each of these combinations, there are 9! ways to permute them. Therefore, the probability of F is 9! p 13 3 Pp 39 6 P * 43! 52! = . 2536 . 1...
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This note was uploaded on 03/31/2008 for the course MATH 331 taught by Professor Anderson during the Spring '08 term at University of Wisconsin.
 Spring '08
 Anderson
 Math, Probability

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