Physics 2 notes tests solutions

Physics 2 notes tests solutions - registered as a new...

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Test 4  fundamentals of physics II  Key 1.  2.  
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3.
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4.  We use Eq. 17–47 with  = 1200 Hz and  = 329 m/s. (a) In this case,  vD  = 65.8 m/s and  vS  = 29.9 m/s, and we choose signs so that   is larger than  f : (b) The wavelength is   =  λ v /  = 0.208 m. (c) The wave (of frequency  ) “emitted” by the moving reflector (now treated as a “source,” so  v = 65.8 m/s) is returned to the detector (now treated as a detector, so  v D   = 29.9 m/s) and 
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Unformatted text preview: registered as a new frequency f ′′ : (d) This has wavelength v / f ′′ = 0.152 m. 5. (a) Approximating n = 1 for air, we have 6. 7. (a) The frequency of the wave is the same for both sections of the wire. The wave speed and wavelength, however, are both different in different sections. Suppose there are n 1 loops in the aluminum section of the wire. Then, 8. 9. (a) For the image formed by the first lens...
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This note was uploaded on 06/07/2009 for the course PHYSICS 2212 taught by Professor Geist during the Fall '09 term at Georgia Perimeter.

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Physics 2 notes tests solutions - registered as a new...

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