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Unformatted text preview: Homework 1 Solutions Physics 213 Fall 2003 Note: These solutions are presented symbolically. Use your numbers given to determine your answer. 1. In a Youngs double-slit experiment, the angle that locates the second dark fringe on either side of the central bright fringe is degrees. Find the ratio of the slit separation d to the wavelength of the light. For the double slit experiment, the bright spots are found at d sin = m ( m = 0 , 1 , 2 , . . . ) , but we want the dark spots, which are at d sin = m + 1 2 . The first dark fringe is at m = 0, and the second dark fringe is at m = 1. Thus, we have d sin = 3 2 . We want the ratio d/ , and we find that d = 3 2 sin . 2. In a Youngs double-slit experiment the separation y between the first-order bright fringe and the central bright fringe on a flat screen is y o m, when the light has a wavelength of o nm. Assume that the angles that locate the fringes on the screen are small enough so that sin tan . Find the separation y when the light has a wavelength of nm. Again, the bright fringe for a double slit experiment is d sin = m, where m = 1 for the first bright fringe. We are not, however, given the angle for either wavelength, but rather the separation y o . That depends on the distance to the screen, which we arent given. For now, lets just call it L . If we knew L we could find by tan = y L . One thing we do know is that the angle is small, so we can say sin tan = y L . This means, for the first fringe, d sin = d y o L = o ....
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This note was uploaded on 06/07/2009 for the course PHYSICS 2212 taught by Professor Geist during the Fall '09 term at Georgia Perimeter.
- Fall '09