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Unformatted text preview: 12kip single = 18kip tandem = 50kip triple = Computed 18kip ESAL = 1449.27 Traffic = 1449.27 (365) 20 = 10,579,671 18kip ESAL Solution (continued) Δ PSI = 4.4 – 2.5 = 1.9 Equation 4.19 gives D = 9.21 in. Are we done yet?? NO Different from assumed 10 in. Need to recalculate ESALs with D = 9 2kip single axle = 10kip single axle (truck) = 22kip tandem (truck) = 12kip single = 18kip tandem = 50kip triple = New 18kip ESAL = 1418.09 [change from 1449.27] Solution (continued) Traffic over 20 years now: 1418.09 (365) (20) = 10, 352,057 18kip ESALs Solving for D = 9.17 in. Close to assumed 9 in. and little change from 9.21 in in first iteration. Being conservative, round up to 9.5 in....
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 Spring '02
 Petrucha
 Truck, 10 inches, single axle, 18 kip, 4.5 million lb

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