MAE 20 Homework_2_SOLUTIONS_summer_2008

MAE 20 Homework_2_SOLUTIONS_summer_2008 - MAE 20 : Summer,...

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MAE 20 : Summer, 2008 Homework 2 (SOLUTIONS) 1. 3 19 22 22 v 3 22 3 8 /cm vacancies 10 5.1 7.41195] exp[ 10 8.47 87)(1358)] 20000/(1.9 exp[ 10 8.47 n atoms/cm 10 8.47 cm) 10 (3.6151 ) atoms/u.c. (4 n 2. /g vacancies 10 5.82 ) g/cm 11.335 1 ( cm) 10 (4.949 cells 125 vacancy 1 cells unit 125 500/4 occupy atoms Pb 500 The (b) g/cm 11.335 atoms/mol) 10 (6.02 cm) 10 (4.949 g/mol) 4)(207.19 (499/500)( ρ ) sites/cell 4 (499/500)( atoms/cell of number The (a) 18 3 3 8 3 23 3 8 3. cells 123.5 in H 1 or 123.5 1/0.0081 is atom H one containing cells of number then the , atoms/cell H 0.0081 is there Since (b) 004 . 0 0081 . 2 0081 . 0 f : Thus atoms. H 0.0081 and atoms Fe 2 include cell per atoms total The ) atoms/cell H ( 0.0081 x atoms/mol) 10 (6.02 cm) 10 (2.866 g/mol) x(1.00797 g/mol) 2(55.847 g/cm 7.882 cell unit a in atoms hydrogen x" " are there Assume (a) H 23 3 8 3
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4. cm 0.179 Δx 7)(673)] 3600/(1.98 xp[ )(0.0012)e Δx 10 2.08 ( s atoms/cm 10 9.47 J s atoms/cm 10 9.47 s/y) 10 536 g/mol)(31. (1.00797
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MAE 20 Homework_2_SOLUTIONS_summer_2008 - MAE 20 : Summer,...

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