Solution3

# Solution3 - 3 23 3 8 / 532 . ) / 10 02 . 6 ( ) 10 5089 . 3...

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Solution 3 3-26. Directions [111] [ 1 1 1] [1 11] [ 11 1] 3-35.

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4-1. 3 22 3 8 / 10 47 . 8 ) 10 6151 . 3 ( . / 4 cm atoms c u atom n × = × = 3 19 22 22 / 10 1 . 5 ) 41195 . 7 exp( 10 47 . 8 ) 1358 )( 987 . 1 ( 000 , 20 exp 10 47 . 8 cm vacancies n v × = × = × = 4-5. (a) 3 20 3 8 / 10 157 . 1 ) 10 5089 . 3 )( 200 ( 1 cm vacancies cm vacancy × = × (b) In 200 unit cells, therefore 399 Li atoms. The atoms/cell are 399/200:
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Unformatted text preview: 3 23 3 8 / 532 . ) / 10 02 . 6 ( ) 10 5089 . 3 ( ) / 94 . 6 )( 200 / 399 ( cm g mol atom cm mol g = =...
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## This note was uploaded on 06/09/2009 for the course MAE 614106 taught by Professor Marcmeyers during the Spring '09 term at UCSD.

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Solution3 - 3 23 3 8 / 532 . ) / 10 02 . 6 ( ) 10 5089 . 3...

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