{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

mgb5e_ppt_6_4 - = x(2 x 1 4(2 x 1 =(2 x 1 x 4 Check(2 x 1 x...

Info icon This preview shows pages 1–4. Sign up to view the full content.

View Full Document Right Arrow Icon
§ 6.4 Factoring Trinomials of the Form x 2 + bx + c by Grouping
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Martin-Gay, Beginning Algebra, 5ed 2 To Factor Trinomials by Grouping 1) Factor out a greatest common factor, if there is one other than 1. 2) For the resulting trinomial ax 2 + bx + c , find two numbers whose product is a · c and whose sum is b . 3) Write the middle term bx , using the factors found in Step 2. 4) Factor by grouping. Factoring by Grouping
Image of page 2
Martin-Gay, Beginning Algebra, 5ed 3 Factoring by Grouping Example : Factor by grouping: 2 x 2 + 9 x + 4 Find two numbers that we can multiply together to get 8 and add together to get 9. ___ × ___ = 8 ___ + ___ = 9 1 1 8 8 The value of ac = 8. Rewrite 9 x as x + 8 x . 2 x 2 + 9 x + 4 = 2 x 2 + x + 8 x + 4 Factor by grouping.
Image of page 3

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 4
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: = x (2 x + 1) + 4(2 x + 1) = (2 x + 1)( x + 4) Check : (2 x + 1)( x + 4) = 2 x 2 + 8 x + 1 x + 4 = 2 x 2 + 9 x + 4 Factor out (2 x + 1). Martin-Gay, Beginning Algebra, 5ed 4 Factoring by Grouping Example : Factor by grouping: 8 x 2 + 10 x-3 (2 x + 3)(4 x-1) = 8 x 2 + 10 x-3 Check: Find two numbers that we can multiply together to get -24 and add together to get 10. ____ × ____ = -24 ____ + ____ = 10 12 12 (-2) (-2) The value of ac is -24. Rewrite 10 x as 12 x + (-2 x ). 8 x 2 + 10 x-3 = 8 x 2 + 12 x-2 x-3 Factor by grouping. = 4 x (2 x + 3) -1(2 x + 3) = (2 x + 3)(4 x-1) Factor out (2 x + 3)....
View Full Document

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern