Molar Mass Determination by Freezing Point Depression.docx - Molar Mass Determining by Freezing Point Depression Submitted by Christina McCool Partner

Molar Mass Determination by Freezing Point Depression.docx...

This preview shows page 1 - 4 out of 4 pages.

Molar Mass Determining by Freezing Point Depression Submitted by: Christina McCool Partner: Chloe Devanny Date of Submission: 2/28/18 Lab Section: CHE111L-21
Image of page 1

Subscribe to view the full document.

Purpose The purpose of this experiment was to determine the molar mass of a soluble unknown compound by measuring the freezing point depression of the solution. Procedure The procedure for this lab can be found on pages 34- 38 in “General Chemistry CHE111L Laboratory Manual Spring 2018”. Data tables Carbon copies of data tables have been attached to the back of this lab report. Calculations 1. T f T f = T f solvent - T f solution Trial 1: 1.875- (-1.18)= 1.37 C Trial 2: 1.875- (-1.65)= 1.84 C Trial 3: 1.875- (-1.25)= 1.44 C 2. Molality T = i K f m Trial 1: 1.37= 2(1.86)m m= 0.37 Trial 2: 1.84= 2(1.86)m m= 0.49 Trial 3: 1.44= 2(1.86)m m= 0.34 3. Number of Moles Solute m= number of moles solute/ kg Solvent Trial 1: 0.37= x/ .02372 x= .0101 mole Trial 2: 0.49= x/ .02372 x= .0117 mole Trial 3: 0.34= x/ .02372 x= .0092 mole 4. Molar Mass MM= Mass of Solute/ Moles of Solute Trial 1: .894/ .0101= 88.51 g/mol Trial 2: .894/ .0117 = 76.41 g/mol Trial 3: .894/ .0092 = 97.17 g/mol
Image of page 2
Summary of Results Unknown Number: 4
Image of page 3

Subscribe to view the full document.

Image of page 4

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern

Ask Expert Tutors You can ask 0 bonus questions You can ask 0 questions (0 expire soon) You can ask 0 questions (will expire )
Answers in as fast as 15 minutes