Determination of the Formula of a metal oxide.docx - Purpose The purpose of this experiment is to prepare a metal oxide and determine its empirical

# Determination of the Formula of a metal oxide.docx -...

• No School
• AA 1
• 4

This preview shows page 1 - 3 out of 4 pages.

Purpose The purpose of this experiment is to prepare a metal oxide and determine its empirical formula. The experiment will also demonstrate the law of constant composition. Procedure The procedure for this lab can be found on pages 35- 39 in “General Chemistry CHEL-110 Laboratory Manual Fall 2017”. Data Tables Carbon copies have been attached to the back of this lab report. Calculations 1. Percent of Magnesium 0.157/ 24.31 X 100 = 55.67% 2. Percent of Oxygen 0.125/ 15.99 X 100 = 44.33 % 3. Number of moles of Magnesium 0.157/ 24.21 = 0.00658 g/mol 4. Number of Moles of Oxygen 0.125/ 15.99 = 0.00782 g/mol 5. Mole ratio 0.00658/ 0.00782 = 0.88 1:0.88 1:1 6. Theoretical Yield (0.157g Mg) (1 mole Mg/ 24.31 g Mg) (1 mole MgO/ 1 mole Mg) (40.3 g Mg/ 1 mole MgO) = 0.26g MgO 7. Percent Yield 0.282 g MgO / 0.26 g MgO X 100= 108.46%

Subscribe to view the full document.

Summary of Results % Mg in Magnesium Oxide 55.46% % O in Magnesium Oxide 44.33% Mole Ratio Mg: O 1:0.88 1:1 Empirical Formula of Magnesium Oxide MgO Theoretical Yield of Magnesium Oxide 0.26 g MgO % Yield of Magnesium Oxide 108.46% Conclusion The purpose of this lab, to prepare a metal oxide and determine its empirical formula and demonstrate the law of constant composition. The results were then used to find the percent of
• Fall '19
• Magnesium, Oxide, Christina McCool, 0.157g Mg

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern

Ask Expert Tutors You can ask 0 bonus questions You can ask 0 questions (0 expire soon) You can ask 0 questions (will expire )
Answers in as fast as 15 minutes