test 3.xlsx - On the basis of extensive tests the yield point of a particular type of mild steel-reinforcing bar is known to be normally distributed

# test 3.xlsx - On the basis of extensive tests the yield...

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sigma n x CI alpha z 100 36 8403 0.9 0.1 1.645 8375.6 8430.4 CI = 98 % alpha = 0.02 a/2 = VALUE OF Z z = 2.33 On the basis of extensive tests, the yield point of a particular type of mild steel-reinforcing bar is known to be normally distributed with σ = 1 a) Assuming this to be the case, if a sample of 36 modified bars resulted in a sample average yield point of 8403 l b, compute a 90 % CI for the b) How would you modify the interval in part (a) to obtain a confidence level of 98 %?

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100. The composition of the bar has been slightly modified, but the modification is not believed to have affected either the normality or the value of e true average yield point of the modified bar. (Round your answers to one decimal place.)
σ .

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Change the RED sample size 4745 0.1275 2.687039E-05 0.0051836657 0.0133531228 0.136647 0.1633531228
samples mean 95% S.D 196 20.7 1.96 3.87 21.2418 20.1582 mpa 6 within 0.5 N 553.1904

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mean 188 sd 7.5 CI 0.98 195.2411 180.7589

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-3.751176
s 1.2 x bar 51.9 sample size 10 standard error 0.3794733192 48 sample t 10.277402396 P 1.424058E-06 0 μHo

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n = 22 µ = 371.61 σ = 25.74 Calculate the test statistic and determine the P-value.

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