answerschapter8

answerschapter8 - Answers to Chapter 8 8.2) 8.6) (a) m =...

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Unformatted text preview: Answers to Chapter 8 8.2) 8.6) (a) m = 195:1 MPa, (b) 3 max = 201:6 MPa, (c) not acceptable (a) W 18 (b) m 35 (S = 57:6 in > Smin = 52:5 in3 ) m = 21:875 ksi (at C), 125 (S = 3510 = 3:06 ksi (at B), max = 20:95 ksi (at C) 8.8) (a) W 690 (b) m 103 mm3 > Smin = 2812:5 mm3 ) m = 128:2 MPa (at C), 129:7 MPa, 37:9 MPa, = 47:3 MPa (at D), = 8:94 MPa, x max = 124:0 MPa (at C) (c) xy 8.32) 8.34) 8.39) 8.41) 8.44) 8.45) (a) (a) (a) A = x = 0, (b) xy = 6:71 MPa, 131:6 MPa, = 111:8 MPa, =0 = = 14:06 MPa, (b) = = =0 = 20:4 MPa, = 14:34 MPa, (b) B 21:5 MPa, = 19:98 MPa max = 65:5 MPa, ( p )A = 30 ; A = B 21:8 MPa, ( p )B = 120 ; = = 43:7 MPa max (a) (a) (c) = 0:579 ksi, ( p )A = 12:1 ; 12:58 ksi, ( p )B = 102:1 , (b) = 21:3 MPa, = 0:293 MPa = 6:58 ksi = 18:39 MPa, = 24:1 MPa, = 0:391 MPa, (b) =0 8:2 ; B B 8.49) 8.69) 8.70) A A = 30:1 MPa, ( p )A = = 0:62 MPa, ( p )B = 81:8 ; 10:59 ksi, ( p )B = 103:3 ; max max = 15:37 MPa = 0:590 ksi, ( p )A = 13:3 ; 14:98 MPa, = = 5:59 ksi = = 17:29 MPa 1 ...
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This homework help was uploaded on 04/01/2008 for the course ESM 2204 taught by Professor Ohanehi during the Spring '08 term at Virginia Tech.

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