answerschapters9and10

answerschapters9and10 - kN 10.26 P all = 4 21 kips 10.27(a...

Info icon This preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Answers to Chapters 9 and 10 9.1) (a) y ( x ) = ° 1 6 Px 2 EI (3 L ° x ) , (b) y B = 1 3 PL 3 EI # , (c) ° B = 1 2 PL 2 EI CW 9.4) (a) y ( x ) = ° 1 24 w EI ° x 4 ° 4 L 3 x + 3 L 4 ± , (b) y A = 1 8 wL 4 EI # , (c) ° A = 1 6 wL 3 EI CCW 9.5) (a) y ( x ) = ° 1 24 w EI ° ° x 4 + 4 Lx 3 ° 4 L 2 x 2 ± , (b) y B = 1 24 wL 4 EI # , (c) ° B = 0 9.17) (a) y ( x ) = 1 90 w 0 EIL 2 ° x 6 ° 3 Lx 5 + 5 L 3 x 3 ° 3 L 5 x ± , (b) ° A = 1 30 w 0 L 3 EI CW (c) y C = 61 5760 w 0 L 4 EI # 9.18) (a) y ( x ) = ° 1 240 w 0 EIL 2 ° 10 L 2 x 4 ° 8 Lx 5 + 2 x 6 ° 10 L 4 x 2 ± , (b) y B = 1 40 w 0 L 4 EI # 9.22) R B = 11 40 w 0 L " 9.68) ° B = 11 6 wa 3 EI CW, y B = 29 24 wa 4 EI # 9.84) R B = 3 2 M 0 L # , M B = 1 4 M 0 CCW 9.91) R C = 8 : 327 kips " , R A = 8 : 779 kips # , R B = 0 : 452 kips " 9.92) R A = 10 : 86 kN " , M A = 1 : 942 kN ± m CCW, R D = 1 : 144 kN " , M D = 0 : 286 kN ± m CW 10.10) (a) P cr = 6 : 65 lb, (b) P cr = 21 : 0 lb 10.12) ( P cr ) a ( P cr ) b = 1 : 421 10.19)
Image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: kN 10.26) P all = 4 : 21 kips 10.27) (a) F:S: = 2 : 29 , (b) d (2) = 1 : 768 in., d (3) = 1 : 25 in., d (4) = 1 : 046 in. 10.28) (1) P all = 2 : 64 kN, (2) P all = 0 : 661 kN, (3) P all = 10 : 57 kN (4) P all = 5 : 39 kN, (5) P all = 2 : 64 kN 1...
View Full Document

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern