SecondOrderSeries-Parallel

SecondOrderSeries-Parallel - Problem # 11 In the above...

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Unformatted text preview: Problem # 11 In the above circuit, the switch closes at t = 0. The source is a steady DC voltage source equal to 50 volts. The current through the inductor at t = (0-) is 0 and the voltage across the capacitor at t = (0- ) is 0. 1. Use KCL to write a differential equation for the voltage across the capacitor. Put this equation in standard form. 2. What is the form of the particular solution ? 3. What is the form for the complementary solution. State your reason for choosing this form of complementary solution. KCL 4.0 +11. driz‘fxzvso 1... tjwdkg—io 1’ lg— P ,_———- >0 No 5.9. @ a K 0a” 0 saw: rm! 0161’ \ W—J ZM— U01, . _L,_ J, (a R: 2 [07 watt 4—” 2 ,___l—___r-—" .. I , _L— 1» C /o-/a° Ions" Io’~/6’°‘ W" S» ,2 1°? _- [o7 ’ o2 _" Zotés cut )Zavl «— u-ndc'] Problem # 1 For the series R, L, C circuit A70 V 1 3 31. Develop a differential equation to solve for the voltage across the capacitor. 6 ‘ 2’2. Solve for the particular solution. ' 3. Solve for 0C and W; and determine the correct form for the complementary solution. You do not have to solve for K1 and K2. 1, -- .Vi__.t/ ' A {j 4. Is this circuit critically damped, under damped, or over damped ? WONG ‘ ' .-_ o "50 l “M '— 5?“ " LL97 Acta 2 C :3U [C $12.95) + LQ dz 1’2”) a, 02m , )5/0 \p our our" Ifo J/ cl‘v’oU) 2 Auwr) * J— at’dt [LC 011:1 L 4,? W Macaw k___-_,L_,_____ Whig 41’1/ ’0 ' '0- M 10:5)(5) (JD-c) 5-0.]: (3::— r [010 46 +_ 2040 U; 5mm: gaicwc Faye—11¢ ls Cpl-1574'U'r a O 91%” ;/ l0~loj 5 ‘ 0&1, 1' +Zoloh’z 3000 /o 353:0 I0 rrz Qo< : lo 10’ 64‘ 5000 M “37“ ’ 2° “’6 fi/ 5 = -5500 t 5; = 52763.31’ &2 Sb: “ {7234-06 é ...
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SecondOrderSeries-Parallel - Problem # 11 In the above...

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