MeshCurrentSupermesh

MeshCurrentSupermesh - DEUEwP Qua Sow” 6L5 Cu KJZ Eur N...

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Unformatted text preview: DEUEwP Qua Sow”; 6L5; Cu. KJZ Eur N 0018 7775 BE CAUSE {luau 75L Uoufiiéi #013955 /T- MOE/mu Ola-Var Maw - szzmr 569 “(4 flow: 5,2. l J: I A“ 717£ Wis/=1 Cu,z,-2.,z~ 2'5 7: DE filmy/L 7/};- E/ocwuc, /u 540/4 ELK.me »%J0 7/7/26 VOLT/{GEE r , U1, V} 19,49 - M1 529m; CuKKE-v' r! 50uil~~>£ L; 4 Pfl—ofierf; IT 5G7” 1/, flap 2;, Fwwma A: /T Z flno wk: 0: No: A) \10 i 0‘ 7/?)5, DE flux: 4 5vu7zf-xz not-51% . ’52:) (of, + vi; +16(fL-I5)¢201’l =50 1i 6 I; + [0 J2“, v" /.§(I5r 12) = O I; A I, = f PZoEi—EM ‘7" + 30 4/167 — 115’ I. .50 I O ’/5’ *3] 5:1. 2 (9 “‘/ '*/ O 1:5 O Emu/MC: Yifi/95 .1, g "'0. 20 9 Am? 1; = ‘7‘: I9"! .1} = 2.31 A»! I,” = 1, -= *0 20‘? A"! 153‘, -= I, 2 ‘ O. 20‘? AM! 120.11, 2' 1‘, 1 _ on 2:0? flnf II I) ’l —- 4-. it’fj " l7"77 ‘232 zfl 1 I} -‘- 2.32 4.49 \/, = f0 \J‘ 13194th C“) fifinde» )5 " /O(f,> 3 5'0 ‘/0 (-0 Z9?) 52. Oi Ughzs \Ja ~ I; 7‘ = 52.07 —(7‘.77)( +> JR.‘7'1‘ dour) U3 — I, (4 +10) a 32.77~ 2.3204) ' ‘7f‘l7 dun Eggwww (<( (( mmmm mm WWW WWW ->> a pwwwam m w m w AA wwww 00 7w¢w¢w n NNNN a." .... fl /Sr ;1:} - :5 ;If1_ *’ C) :i:3 —le +711 +713 0,2: '/11 “big I S? ‘ :3 (3 ,1:' [C9 " L3 57 I C7' :j:z. :3 <3 (:3 " I 1 1123. ..f—— Ii) M] m z [B] I ~O 3°)? I z RAKE z ~5‘7 flhobLth 2 _ Io 11- fif-ga /°« / a :SLchr fi4°1k Laol/ /OI, *3(II'IL) +51)" mm Max Mia-I.) + #11 fl :;II. =. lc) ‘= (I) =: l (:3 It ,7; H-IL LumLouqu xxxx En: <<<< <( 3333 DD mmmm mm ,. W. A. Use meshrcurrent analysis to solve for the mesh currents in the circuit shown below. 61:. No. 937 811E Engineer's Computation Pad ESTAEDTLEK (B 15) 1'5 = /o o ‘of, ID 0 1,= 31‘, -/oo + 7013,12,) =0 1; mm. *HI. = «A? /C.7;r 3. lfI/L M3: 7(284 #47) "#228 '0-2' (I; *6 1:3 .. ’03—- ‘ygo (1’2) O + o :23 =lao f 1013 e “[00 - 73": -' 7‘1; 237‘ o I. O ‘7 D 1.. : [DD “7" I0 I, —Ioc 7(1—1—1’.) + 7133,43,) +v¢,, = o * #(aac-(‘6.oc>) = "Var 4- 6168 = *qu Udgp 4' "/fiébv Engineer's Computation Pad N0. 937 811E Vx .— (jg-1.37 -' (7.85-Vé9)? - “T238 0.2Ux = —-<235 @STAEDTLER“ W A. Use mesh—cment analysis to solve for the mesh currents in the circuit shown below. B. Use the mesh currents to determine the voltage across and the current through the dependent source. Engineer‘s Cornpuzataun Pad N0. 937 8| 1E 3 STAEDTLER‘Q' (4) (a) 4’ *(IL'I-JDSO 7(13-13) *6C33'1?) ‘30 ‘0 .- «rffi r21; vulva) *0 (o> If, 3 "jar -3 7 —+ -'r f. O o ‘7' Io ‘6 IL = ‘0 o o ‘4 12 I: 0 I O c: O fir 5’ CfiWl—aal = 5;} I; ' 16.20 I; g /6-"'# J;- = 82“ D: rim at V95?! )9” 75". U. 3) U031" 7'77. = *C’fi)‘ 76’8"? : ‘528 PM 1: 5w 3) ngP ’ If‘fa— #62 t -8 H ...
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