Standing Waves in Strings and Air Columns

# Standing Waves in Strings and Air Columns - Standing Waves...

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Standing Waves in Strings and Air Columns February 6 th , 2007 Pre-Questions : 1. f  x     λ = v      1/s x m = m/s 2. μ (kg/m) = M of string / L of string = 0.001 kg/5m  f 2    x   λ 2  = F T  /  μ (120Hz) 2   x  (1) 2   =  F T  / 0.001 kg/5m F T  = 2.88 N F = m x g 2.88N = m x 9.81m/s 2   m = 0.29 kg Purpose:  To test Newton’s Laws applied to strings and air columns. Method:  The procedure was followed (15.1 – 15.4), and part b was only observed. Diagram:

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Data:  See attached spreadsheet Results: Calculations : Equation: F = mg n= 2 F = 2.630 kg x  9.81 m/s 2 = 25.800 N n=3 F = 1.178 kg x  9.81 m/s 2 = 11.556 N n=4 F = 0.640 kg x  9.81 m/s 2 = 6.278 N n=5 F = 0.410 kg x  9.81 m/s 2 = 4.022 N μ (kg/m) = M of string / L of string
μ  = 0.00131kg/m Predicted frequency = 120 Hz Experimental frequency:  Slope =  μ  x f 2 = 113.009 Hz   Graph : See attached spreadsheet Error Calculation :

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• Spring '07
• Conroy
• Physics, Wavelength, Standing wave, Air Columns, 0.29 kg, 0.00131kg

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