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Unformatted text preview: Chemistry 222 Chapter 8 Problems 8.9 Draw a structural formula for each amine: 8.11 Classify each amino group as primary, secondary, or tertiary; and as aliphatic or aromatic. NH 2 Br N NH 2 NH 2 NH 2 H 2 N NH 2 NH 2 Br N a. 2-butanamine b. 1-octanamine c. 2,2-dimethyl-1-propanamine d. 1,5-pentanediamine e. 2-bromoaniline f. N,N-dibutyl-1-butanamine N H NH 2 HO a. Serotonin (a neurotransmitter) primary aliphatic secondary heterocyclic aromatic 8.17 2-methylpropane (bp -12 o C), 2-propanol (bp 82 o C), and 2-propanamine (bp 32 o C), all have approximately the same molecular weight, yet their boiling points are quite different. Explain the reason for these differences. 2-methylpropane is incapable of making hydrogen bonds. Both 2-propanol and 2-propanamine make intermolecular hydrogen bonds as liquids. Those in 2-propanol are O-H----O bonds, and those in 2-propanamine are N-H----N bonds. O and H have a greater electronegativity difference than N and H. The larger electronegativity difference between O and H gives the hydroxyl O a greater partial negative charge than the amine N, and the hydroxyl H a greater partial positive...
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This note was uploaded on 04/01/2008 for the course CHEM 222 taught by Professor Mullen during the Spring '08 term at Texas A&M.
- Spring '08