100%(11)11 out of 11 people found this document helpful
This preview shows page 1 - 3 out of 5 pages.
Rania Farooq0621720Lab 3 and 4 AssignmentTable 1. Volumes that will be used to generate solutions containing a known concentration of BSA (7 marks)12345678LabelBSA concentration (µg/ml)Volume of stock BSA (µl)Volume of 0.15N NaCl (µl)Total Volume (µl)A595 nmTube Set 1A595 nmTube Set 2A595 nmAverageTube 100100100000Tube 2255951000.030.040.035Tube 35010901000.130.120.125Tube 47515851000.160.180.17Tube 510020801000.270.270.265Calculations (2 marks) Show sample calculations for columns 3 and 4.Calculation for column 3:** Using tube 2 to calculate for volume of stock BSA (µl):** 500 µg/ml solution of BSA was obtained from the TA. Since the answer needed to be in microliters (µl), 500 µg/ml was converted into 0.5 µg/µl** Tube 2 was to contain 25 µg/ml of 0.15N NaCl and this was also converted to units of microliter. 25 µg/ml 0.025 µg/µlC1V1 = C2V2(0.5 µg/µl) (x) = (0.025 µg/µl) (100 µl)x = ((0.025 µg/µl) (100 µl)) / (0.5 µg/µl)x = 5 µl** The calculations for tubes 3, 4, and 5 were performed the same way by simply changing the (C2) – BSA concentration µg/µl for each respective tube** Tube 3 consisted of 0.050 µg/µl BSA concentration, tube 4 consisted of 0.075 µg/µl BSA concentration, and tube 5 consisted of 0.100 µg/µl BSA concentrationCalculation for column 4:** Using tube 2 to calculate for the volume of 0.15N NaCl (µl):** The total volume in each tube was supposed to be 100 µl** tube 2 consisted of 5 µl of stock BSA:x = 100 µl – 5 µlx = 95 µl1