BIOL 2070 - Lab 3 and 4 Assignment .docx - Rania Farooq 0621720 Lab 3 and 4 Assignment Table 1 Volumes that will be used to generate solutions

# BIOL 2070 - Lab 3 and 4 Assignment .docx - Rania Farooq...

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Rania Farooq 0621720 Lab 3 and 4 Assignment Table 1. Volumes that will be used to generate solutions containing a known concentration of BSA (7 marks) 1 2 3 4 5 6 7 8 Label BSA concentratio n (µg/ml) Volume of stock BSA (µl) Volume of 0.15N NaCl (µl) Total Volume (µl) A595 nm Tube Set 1 A595 nm Tube Set 2 A595 nm Average Tube 1 0 0 100 100 0 0 0 Tube 2 25 5 95 100 0.03 0.04 0.035 Tube 3 50 10 90 100 0.13 0.12 0.125 Tube 4 75 15 85 100 0.16 0.18 0.17 Tube 5 100 20 80 100 0.27 0.27 0.265 Calculations (2 marks) Show sample calculations for columns 3 and 4. Calculation for column 3: ** Using tube 2 to calculate for volume of stock BSA (µl): ** 500 µg/ml solution of BSA was obtained from the TA. Since the answer needed to be in microliters (µl), 500 µg/ml was converted into 0.5 µg/µl ** Tube 2 was to contain 25 µg/ml of 0.15N NaCl and this was also converted to units of microliter. 25 µg/ml 0.025 µg/µl C 1 V 1 = C 2 V 2 (0.5 µg/µl) (x) = (0.025 µg/µl) (100 µl) x = ((0.025 µg/µl) (100 µl)) / (0.5 µg/µl) x = 5 µl ** The calculations for tubes 3, 4, and 5 were performed the same way by simply changing the (C 2 ) – BSA concentration µg/µl for each respective tube ** Tube 3 consisted of 0.050 µg/µl BSA concentration, tube 4 consisted of 0.075 µg/µl BSA concentration, and tube 5 consisted of 0.100 µg/µl BSA concentration Calculation for column 4: ** Using tube 2 to calculate for the volume of 0.15N NaCl (µl): ** The total volume in each tube was supposed to be 100 µl ** tube 2 consisted of 5 µl of stock BSA: x = 100 µl – 5 µl x = 95 µl 1