chem prac 8.pdf - Chapter 19 Practice Problems 1 Acetic acid is a weak monoprotic acid with Ka = 1.8 x 10-5 In an acid-base titration 100 mL of 0.100 M

chem prac 8.pdf - Chapter 19 Practice Problems 1 Acetic...

This preview shows page 1 - 2 out of 2 pages.

Chapter 19 Practice Problems 1) Acetic acid is a weak, monoprotic acid with K a = 1.8 x 10 -5 . In an acid-base titration, 100 mL of 0.100 M acetic acid is titrated with 0.100 M NaOH. What is the pH of the solution: a) before any NaOH is added b) after addition of 15.0 mL of 0.100 M NaOH c) at the half-equivalence point d) after addition of a total of 65.0 mL of 0.100 M NaOH d) at the equivalence point e) after addition of a total of 125.0 mL of 0.100 M NaOH 2) Calculate the pH of a buffer consisting of 0.50 M HF and 0.45 M NaF before and after addition of 0.40 g NaOH to 1.00 L solution. K a of HF = 6.8 x 10 -4 3) Calculate the pH of a solution made by adding 0.50 mole of HNO 2 and 0.10 mole of KNO 2 to enough water to make a 1.0 L solution. K a for HNO 2 is 4.5 x 10 -4 at 25 0 C. 4) Indicate which of the following solutions are buffer solutions. A solution containing: a) 0.100 M HNO 2 and 0.070 M HCl b) 0.250 M HNO 3 and 0.250 M HNO 3 b) O.500 M acetic acid (HC 2 H 3 O 2 ) and 0.400 M sodium acetate (NaC 2 H 3 O 2 ) c) 0.250 M HNO 2 and 0.100 M NaNO 3 5) Determine the concentrations of Ba 2+ , H 3 O + , OH - , HC 2 H 3 O 2 , C
Image of page 1

Subscribe to view the full document.

Image of page 2
  • Fall '16
  • buffer solution, 0.50 m, 0.45 m

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern

Ask Expert Tutors You can ask 0 bonus questions You can ask 0 questions (0 expire soon) You can ask 0 questions (will expire )
Answers in as fast as 15 minutes