# data assignment unit 6.pdf - 1 During a recent survey of...

• No School
• AA 1
• 12

This preview shows page 1 - 4 out of 12 pages.

1. During a recent survey of ethnic backgrounds of 1000 people in a large city, 513 were Canadian, 148 were French, 72 were African and 56 were Asian and the remainder were from other groups. Calculate the probability that a person, selected at random from the population has: a. a Canadian background? P(Canadian) = Number of Favorable Outcomes/Total Number of Possible Outcomes P(Canadian) = 513/1000 P(Canadian) = 0.513 Therefore, the probability that the selected person has a Canadian Background is 0.513 b. an African background? P(African) = Number of Favorable Outcomes/Total Number of Possible Outcomes P(African) = 72/1000 P(African) = 0.072 Therefore, the probability that the selected person has an African background is 0.072 c. an “other” background? 1000 (513 + 148 + 72 + 56) = 211 P(“other”) = 211/1000 P(“other”) = 0.211 Therefore, the probability that the selected person has an “other” background is 0.211 2. A spinner is divided into three equally sized regions as shown. The spinner is spun twice. For each probability you determine, express your answer as a fraction, decimal and percent. a. What is the probability of spinning A on the first spin? P(A) = 1/3 P(A) = 0.33 P(A) = 33% Therefore the probability of spinning A on the first spin is 1/3 in a fraction, 0.33 in a decimal, or 33% in a percent.

Subscribe to view the full document.

b. Draw a tree diagram to represent the sample space for both spins. c. What is the probability of spinning A followed by B? P (A, B) = 2/9 P (A, B) = 0.22 P (A, B) = 0.22 x 100 P (A, B) = 22.2% Therefore, the probability of spinning A followed by B is 2/9 in a fraction, 0.22 in a decimal or 22.2% in a percent. d. What is the probability of getting the same letter on both spins?
P (A, A) = 1/9 P (B, B) = 4/9 P (A, A + B, B) = 1/9 + 4/9P (A, A + B, B) = 5/9 P (A, A + B, B) = 0.55 P (A, A + B, B) = 0.55 x 100 P (A, A + B, B) = 55.5% Therefore, the probability of getting the same letter on both spins is 5/9 in a fraction, 0.55 in a decimal, or 55.5% in a percent. 3. Binomial i. The Binomial Distribution s used when we have a fixed number of trials, in which they have two outcomes (win or loose). To use this formula, along with the number of trials and the two outcomes, we also need to know the probability of success and how many successes we want. ii. The formula for this the Binomial Distribution is: The first part of the equation n C x is used because we need to first determine the number of successes ( x ) that we can get from the total number of trials ( n ) . Order does not matter which is why we would use the combination equation for this. The second part of the equation is p x . P represents the probability of success. The reason we have to calculate the probability of success to the power of the number of wanted successes is because we want to find the probability of getting the number of successes we want. (1 p ) ( n x ) is the last part of the equation. (1 p ) is done because the difference equals the probability of not succeeding. This number is to the power of ( n x ) because since (1 p ) ( n x ) represents the probability of not succeeding, we need to minus the total number of trials by the number of wanted successes to find out how many of the total trials are not successes.

Subscribe to view the full document.

• Fall '19
• Probability theory, Binomial distribution, Hypergeometric Distribution

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern

Ask Expert Tutors You can ask 0 bonus questions You can ask 0 questions (0 expire soon) You can ask 0 questions (will expire )
Answers in as fast as 15 minutes