Week 6 Chapter 10 Problem Set.xlsx - A Alternate Ha u00b51...

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A. Alternate Ha : µ1 < µ2 Null hypothesis B. The Type I error would be the probability of rejecting the mean number of calories in the cheeseburger is higher or equal to the people who thought about cheesecake first than those that thought about organic C. The Type II error is the probability of accepting the mean number of calories in the cheeseburger is higher or equal to the people who thought about cheesecake first than those that thought about organic D. The t Stat -6.1532 is smaller than the critical bound of -2.4286. There is enough evidence to reject the null hypothesis and accept the mean number of calories in the chee Pooled Variance 16384 19600 19xSQRT128+19xSQRT140 683696 17992 19+19 38 Tstat (780-1041)-0 -261 -261 -6.153197 SQRT 17992 *(0.1) 1799.2 20 20 Critical Value d.f= n1 +n2-2 20+20-2 38 Ho: µ1 > µ2 SQRT 17992*(1 +1 ) T ditribution table we have - t (0.01,38)= -2.4286
c fruit salad is higher. c fruit salad is lower. eseburger is lower for the people
A. At 0.05 significance level, we can reject the null hypothesis because p-value (0.035195138) is less than the significance level (0.05). Thus, we can conclude that there is a difference between the technology sector and

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