Chapter7.doc - CHAPTER 7 THE ELECTRONIC STRUCTURE OF ATOMS 141 CHAPTER 7 THE ELECTRONIC STRUCTURE OF ATOMS 7.7 7.8(a c 3.00 108 m/s 3.5 10 6 m 3.5 103

# Chapter7.doc - CHAPTER 7 THE ELECTRONIC STRUCTURE OF ATOMS...

• Homework Help
• 19

This preview shows page 1 - 3 out of 19 pages.

CHAPTER 7: THE ELECTRONIC STRUCTURE OF ATOMS CHAPTER 7 THE ELECTRONIC STRUCTURE OF ATOMS 7.7 (a) 8 6 13 3.00 10 m/s 3.5 10 m 8.6 10 /s 3 3.5 10 nm c (b) 8 14 9 3.00 10 m/s 5.30 10 /s 566 10 m 14 5.30 10 Hz c 7.8 (a) Strategy: We are given the wavelength of an electromagnetic wave and asked to calculate the frequency. Rearranging Equation (7.1) of the text and replacing u with c (the speed of light) gives:   c Solution: Because the speed of light is given in meters per second, it is convenient to first convert wavelength to units of meters. Recall that 1 nm 1 10 9 m (see Table 1.3 of the text). We write: 9 9 7 1 10 m 456 nm 456 10 m 4.56 10 m 1 nm Substituting in the wavelength and the speed of light (3.00 10 8 m/s), the frequency is: 8 7 m 3.00 10 s or 4.56 10 m 14 1 14 6.58 10 s 6.58 10 Hz c Check: The answer shows that 6.58 10 14 waves pass a fixed point every second. This very high frequency is in accordance with the very high speed of light. (b) Strategy: We are given the frequency of an electromagnetic wave and asked to calculate the wavelength. Rearranging Equation (7.1) of the text and replacing u with c (the speed of light) gives:   c Solution: Substituting in the frequency and the speed of light (3.00 10 8 m/s) into the above equation, the wavelength is: 8 9 m 3.00 10 s 0.122 m 1 2.45 10 s   c 141

Subscribe to view the full document.

CHAPTER 7: THE ELECTRONIC STRUCTURE OF ATOMS The problem asks for the wavelength in units of nanometers. Recall that 1 nm 1 10 9 m. 9 1 nm 0.122 m 1 10 m 8 1.22 10 nm 7.9 Since the speed of light is 3.00 10 8 m/s, we can write 8 8 1.61 km 1000 m 1 s (1.3 10 mi) 1 mi 1 km 3.00 10 m 2 7.0 10 s Would the time be different for other types of electromagnetic radiation? 7.10 A radio wave is an electromagnetic wave, which travels at the speed of light. The speed of light is in units of m/s, so let’s convert distance from units of miles to meters. (28 million mi 2.8 10 7 mi) 7 10 1.61 km 1000 m ? distance (m) (2.8 10 mi) 4.5 10 m 1 mi 1 km Now, we can use the speed of light as a conversion factor to convert from meters to seconds ( c 3.00 10 8 m/s). 10 2 8 1 s (4.5 10 m) 1.5 10 s 3.00 10 m ? min 2.5 min 7.11 8 2 1 3.00 10 m/s 3.26 10 m 9192631770 s 7 3.26 10 nm c This radiation falls in the microwave region of the spectrum. (See Figure 7.3 of the text.) 7.12 The wavelength is: 7 1 m 6.05780211 10 m 1,650,763.73 wavelengths   8 7 3.00 10 m/s = 6.05780211 10 m 14 1 4.95 10 s c 7.15 34 8 9 (6.63 10 J s)(3.00 10 m/s) 624 10 m   19 3.19 10 J hc h E 7.16 (a) Strategy: We are given the frequency of an electromagnetic wave and asked to calculate the wavelength.
• Spring '16
• lee sung chul

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern

Ask Expert Tutors You can ask 0 bonus questions You can ask 0 questions (0 expire soon) You can ask 0 questions (will expire )
Answers in as fast as 15 minutes