Physics CH 5 CLSSWRK.pdf - (5-1 A child sitting 1.20m from the center of a merry-go-round moves with a speed of 1.10m/s Calculate aR=v^2/r FR=maR(a the

# Physics CH 5 CLSSWRK.pdf - (5-1 A child sitting 1.20m from...

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(5-1) A child sitting 1.20m from the center of a merry-go-round moves with a speed of 1.10m/s. Calculate aR=v^2/r FR=maR (a) the centripetal acceleration of the child aR=V^2/r= (1.10m/s^2)/(1.20m)= =1.01m/s^2 (b) the net horizontal force exerted on the child (mass=22.5kg) FR=maR=(22.5kg)(1.01m/s^2)= =22.7N (5-2) A jet plane traveling 1890km/hr(525m/s) pulls out of a dive by moving in an arc of radius 5.20km. What is the planes acceleration in g’s? a=v^2/r= (525m/s^2)/(5.20km)(1000)= a=53m/s^2= a=5.4g (5-3) A horizontal force of 310N is exerted on a 2.0kg ball as it rotates (at arm length) uniformly in a horizontal circle of radius 0.90m. Calculate the speed of the ball. F=mv^2/R= 310N=2.0kg(v^2)/0.90m= v=11.81m/s (5-7) A car drives straight down toward the bottom of a valley and up the other side on a road whose bottom has a radius of curvature of 115m. At the very bottom, the normal force on the driver is twice his weight. At what speed was the car traveling? FR=m(v^2/r)= FN=FR+mg= 2mg=FR+mg= FR=2mg-mg= FR=mg FR=m(v^2/r)= mg=m(v^2/r)= v= (gr)= (9.8m/s^2)(115m)= = 34m/s (5-9) What is the maximum speed with which a 1200kg car can round a turn of radius 90.0m on a flat

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