Physics CH 3 HW.pdf - ⃗(3-3 If Vx = 9.80 units and Vy = −6.40 units determine the magnitude and direction of V V=�(Vx^2 Vy^2)= =�(9.80)^2-6.40)^2=

Physics CH 3 HW.pdf - ⃗(3-3 If Vx = 9.80 units and Vy =...

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(3-3) If Vx = 9.80 units and Vy = 6.40 units, determine the magnitude and direction of V . V= ( Vx^2+Vy^2 ) = = ( 9.80 ) ^2+ ( -6.40 ) ^2= 11.70magnitude =tan^-1(Vy/Vx)= = ⍬=tan^-1 ( -6.40 / 9.80 ) = -33.1 direction (3-6) Vector V 1 is 6.6 units long and points along the negative x axis. Vector V 2 is 8.5 units long and points at +55 to the positive x axis. (a) What are the x and y components of each vector? V1= (-6.6) V2y=(0) =(-6.6, 0) V2x=(8.5 * cos55=0.0221)=(1.88) V2y=(8.5 * sin55)=(8.49) =(1.88, 8.49) (b) Determine the sum V 1 + V 2 (magnitude and angle). magnitude= (1.90^2+8.49^2) =(8.70) angle= tan^-1(8.49/1.90) =(0.249) (3-8) An airplane is traveling 835 km/h in a direction 41.5 west of north (Fig. 3-34 on pg. 68). (a) Find the components of the velocity vector in the northerly and westerly directions. North= (835km/h)*cos(41.5)= Vnorth=(625.3km/h) West= (835km/h)*sin(41.5)= Vwest=(553.2km/h) (b) How far north and how far west has the plane traveled after 1.75 h? North= (625.3km/h)(2h)= Dnorth=(1250.6m) West= (553.2km/h)(2h)= Dwest=(1106.4m) (3-18) A diver running 2.5m/s dives out horizontally from the edge of a vertical cli ff and 3.0s later reaches the water below. How high was the cli ff and how far from its base did the diver hit the water? ux=2.5m/s uy=0 ax=0 ay=9.8m/s^2 h=uyt+1/2ayt^2=1/2*9.8m/s^2*3.0s^2= 44.1m x=uxt+1/2*axt^2=(2.5m/s)*3s= 7.5m (3-23) A fire hose held near the ground shoots water at a speed of 6.5m/s. At what angle(s) should the nozzle point in order that the water land 2.5m away (see Fig. 3-36 on pg. 69)?

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