hw11sol_fall03

# hw11sol_fall03 - AMS 310.01 FALL 2003 Homework#11 Solutions...

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AMS 310.01  FALL 2003   Homework #11  Solutions  7.56   In this problem, the alternative is two sided and  0.05 α =  so we use Table 8(c) with  8 n = (a)  0.50 , (Type II error) 0.68 d P = = (b)  0.75 , (Type II error) 0.40 d P = = (c)  1.00 , (Type II error) 0.18 d P = = (d)  1.25 , (Type II error) 0.05 d P = = (e)  1.50 , (Type II error) 0.01 d P = = <<  Using the formula >> 0 1 (Type II error) (acceptance H | H is true) P P =   * Acceptance region of Ho :   0 /2 /2 / x z z n α α μ δ - - < <         0 /2 0 / 2 z x z n n α α σ σ μ μ - < <
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