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Unformatted text preview: (f) 9 6 ( ;9,0.7) k b k = = 1  B(5; 9, 0.7) = 1(0.2703) = 0.7297 4.16 (a) b(1;12, 0.05) = B(1;12, 0.05) – B(0;12,0.05) = (0.8816)(0.5404) = 0.3412 (b) B(2; 12, 0.05) = 0.9804 (c) 1 B(1;12, 0.05) = 1(0.8816)=0.1184 4.18 (a) The probability that 1 or more components in a sample of 15 is defective when the true probability of being good is 0.95 , is 1  b(0;15, 0.05) = 1 15 (0.95) = 0.5367 (b) The probability that 0 are defective when the true probability is 0.90 is b(0; 15, 0.10) = 0.2059 (c) When the true probability is 0.90, we have b(0; 15, 0.20)= 0.0352...
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 Fall '03
 Mendell
 1 K, Power of two, Live Aid, Centered pentagonal number, bad tires

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