HW_13 Solutions - Z = 0.012in = 0.002 6in Since the...

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002 . 0 6 012 . 0 = = in in Z e Since the Material is Confined 0 = = Y X e e Using Generalized Hooke’s Law with thermal strains [ ] ( 29 [ ] ( 29 [ ] ( 29 [ ] ( 29 [ ] ( 29 [ ] ( 29 20 . 6 35 . 0 0 200 ) 1 10 ( 1 . 13 35 . 0 ) 10 ( 10 1 002 . 0 1 2 . 26 35 . 0 0 200 ) 1 10 ( 1 . 13 35 . 0 ) 10 ( 10 1 0 1 2 . 26 35 . 0 0 200 ) 1 10 ( 1 . 13 35 . 0 ) 10 ( 10 1 0 1 6 6 6 6 6 6 + + - = + + - = + - - = + + - = + + - = + - - = + + - = + + - = + - - = - - - Y X Z Y X Z Y X Z Z Z X Y Z X Y Z X Y Y Z Y X Z Y X Z Y X X F F psi T E F F psi T E F F psi T E s s s s s s a us us s e s s s s s s a us us s e s s s s s s a us us s e Solving the three equations simultaneously yields the solution ksi ksi Z X Y 2 . 55 70 - = - = = s s s
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