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Unformatted text preview: #435 Find Reaction forces on base Free Body Diagram on right Sum the Moments about the yaxis .37542*750.4*.2*750lbNftftlbNftlbNftlbMMCCCYY=====Sum the moments about the xaxis BABAXNNNNM===)2()2(Sum the Forces on the body lbNlbNNNNNNFCBAAABAX3755.187375750375====+=++=#437 Find Reactions at A, B and P Free Body Diagram Sum the Moments about the yaxis lbftftlbPftPlbftlbMMYY7515.*150.1*.5.*150=====Sum the moments about the xaxis lbBBMZZX75)4()2(150==+=Sum the moments about the Zaxis lbPBPBMxXX5.1122)3(754)6()6()4(=====Sum the Forces on the body ydir ==YYAFXdir lbAPBAFXXXX5.37==+=Zdir lbABAFZZZZ75150==+=Free Body Diagram To lift pipe we have to have the friction force be half the weight since two sides BsBNWFm=2Sum the moments about point c ===2)(212)()(2dFbWhNdFhNbWMBBBBCKnow FB relation from friction =22dbhWNBUsing the inequality from the first statement about the friction also...
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This note was uploaded on 04/01/2008 for the course ME 211 taught by Professor Thouless during the Spring '08 term at University of Michigan.
 Spring '08
 Thouless

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