HW_4 Solutions - FBD of just the pulley first Now let’s...

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Unformatted text preview: FBD of just the pulley first Now let’s look at member BED: FBD 300 300 300 600 600 ) 6 ( 300 ) 3 ( = + +- = = =-- = =- = ∑ ∑ ∑ X X X Y Y Y Y Y B B E lb F lb B B lb lb F lb E ft ft E M Too Many unknowns Move to member FEC lb E ft lb ft E M X X C 225 ) 3 ( 300 ) 4 ( = =-- = ∑ Using this result in the previous equation lb B B lb F X X X 75 225 300 = = + +- = ∑ Back to Bar FEC lb C C lb F X X X 75 225 300 = = +- = ∑ Member ABC lb C ft lb ft lb ft C ft lb M Y Y A 100 ) 3 ( 300 ) 4 ( 75 ) 6 ( ) 8 ( 75 = = + +-- = ∑ Member BC is a two force member Thus we really only need to look at the arm and lever First FBD of Handle lb A lb A F lb A lb A F lb F in lb in F M X Y Y X X X CB BC A 6 5 . 37 6 6 5 . 37 ) 25 ( 6 ) 4 ( = = +- = = =- = = =- = ∑ ∑ ∑ Equal and opposite forces acting on other bar. FBD lb F in F in lb in lb M D 42 . 9 ) 39 ( ) 5 ( 6 ) 9 ( 5 . 37 = = +-- = ∑ Start with FBD of Bucked CA is two force member kip lb F ft lb ft F ft F M AC AC AC E 51 . 2 2512 ) 5 . 1...
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HW_4 Solutions - FBD of just the pulley first Now let’s...

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