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First Draw FBD of whole structure. (a) Sum Moments about E lbEEFlbEEFlbDftDftlbftlbMYYYXXXYYE350030065050005006500)6()3(300)6(500==--==∴=+-===-+=∑∑∑Next move to member BC see FBD (c) XYYXXYYYYYBBCCBFlbBBFlbCftCftlbM==+-===++-===+-=∑∑∑015001503001500)3()5.1(300Need to Move to next Member to solve. FBD (b) lbBftBftlbftlbMXXA5750)3()5.1(150)3(650==++-=∑Find Magnitude of resultant force lbBBFFYXCB24.5941505752222=+=+==Use shear stress formula Remember since double shear use either twice area Or half the force ksipsiinlbAVCBCB05.6605325.04224.59422======ttptt
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