HW_10 Solutions - Due to Symmetry we can find support loads...

Info icon This preview shows pages 1–5. Sign up to view the full content.

Due to Symmetry we can find support loads 4 3 4 2 2 P R P P R F A A = - - = Section Properties 3 4 6 2 3 3 3 00006 . 0 ) 04 . 0 )( 03 . 0 )( 05 . 0 ( ' ' ) 10 ( 68 . 6 ) 05 . 0 )( 04 . 0 )( 03 . 0 ( ) 04 . 0 )( 03 . 0 ( 12 1 2 ) 06 . 0 )( 02 . 0 ( 12 1 12 1 m Q m m m A y Q m I m m m m m m bh I = = = = + + = = - Max Shear stress at ends. Find Load from shear stress N P Pa m m m P It VQ 238 000 , 80 ) 02 . 0 ( ) 10 ( 68 . 6 ) 00006 . 0 ( 4 3 4 6 3 = = = = - t
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.