Internal energy change of an ideal gas.docx - Internal energy change of an ideal gas deltaU = n*cv*deltaT First law of thermodynamics Q = deltaU W The

# Internal energy change of an ideal gas.docx - Internal...

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Internal energy change of an ideal gas: deltaU = n*cv*deltaT First law of thermodynamics: Q = deltaU + W The only source of Q is her human body. W is 0 because the room is constant volume. Thus: Q = n*cv*deltaT What is the molar isochoric specific heat of an ideal gas? cv = R/(k - 1) What is k? The adiabatic index. For air, oxygen and nitrogen, k=1.4. (I hope she is immersed in air, and not suffocated in pure Argon or pure CO2) Thus" Q = n*R*deltaT/(k - 1) Solve for deltaT: deltaT = Q*(k - 1)/(n*R) Number of moles in terms of number of molecules:

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• Spring '19
• Engr. Wendel Basbas

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