G.docx - (G*m1*m2(r2 Force due to left mass F =(G(370(370(0.152 F = 4.056 10-4 Force due to left mass F =(G(370(370(0.382 F = 6.324 10-5 Since the first

# G.docx - (G*m1*m2(r2 Force due to left mass F...

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(G*m1*m2) / (r2) Force due to left mass: F = (G)(370)(370)/(0.152) F = 4.056 * 10-4 Force due to left mass: F = (G)(370)(370)/(0.382) F = 6.324 * 10-5 Since the first force is to the left and the second is tothe right the net force is:

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• Spring '19
• Engr. Wendel Basbas

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