If a cell’s Ψ P = 3 bars and its Ψ S = -45 bars, what...

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Name KEY Block Date AP Water Potential Practice 1. If a cell’s Ψ P = 3 bars and its Ψ S = -4.5 bars, what is the resulting Ψ? Ψ
2. The cell from question #1 is placed in a beaker of sugar water with Ψ S = -4.0 bars. In which direction will the net flow of water be?
3. The original cell from question # 1 is placed in a beaker of sugar water with Ψ S = -0.15 MPa (megapascals). We know that 1 MPa = 10 bars. In which direction will the net flow of water be?
4. The value for Ψ in root tissue was found to be -3.3 bars. If you take the root tissue and place it in a 0.1 M solution of sucrose at 20°C in an open beaker, what is the Ψ of the solution, and in which direction would the net flow of water be? Ψ p

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