PracticeQuiz3-3.pdf - Practice We are 3 Quiz 3 2...

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Practice Quiz 3 # 3 2 , W We are considering LW where we are given L W , W 2 And by properties on the norm , hw So , we have 2 Lw Ii hw , aw e) , hw hw , LW , LW by bin linearity I conjugate 2 × , W d w , Ld w , w by bin linearity 2 2 L , W d , W Ld W by Hermitian property Now , we will sub in L , but first write out what x is Aside : since W , W Wlw , Wnwn W , W Wlw , Wnwn 2 2 W , Wn Wlw , Wnwn Wlw , Wnwn 2 2 W , Wn
- ( w ' :/ a w W , W , W , W L 2 w W , W , W W , W , W , W 2 W , W w So , 2 2 × , W d , W L L W 2 , W , W ,

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