EECS
2006Spring-Midterm1-Solution

# 2006Spring-Midterm1-Solution - EE 105 Midterm-1 Solution...

• Notes
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φ p 60 mV log Na ni := φ p 0.48 = φ b φ n φ p := φ b 0.84 = xd Vd ( ) 2 ε s φ b Vd ( ) q 1 Na 1 Nd + := xd 0.7 ( ) 1.353 10 5 × = Cj ε s xd 0.7 ( ) Area := Cj 7.656 10 14 × = F (2) Nd 10 16 := tox 20 nm := φ n 60 mV log Nd ni := φ n 0.36 = φ pp 550 mV := V_FB φ n φ pp := V_FB 0.91 = V (a) Xd_max 2 ε s 2 φ n ( ) q Nd := Xd_max 3.053 10 5 × = Qb_max q Nd Xd_max := Cox ε ox tox := V_Tp V_FB 2 φ n Qb_max Cox := V_Tp 0.093 = EE 105 Midterm-1 Solution Prof. Ming C. Wu Spring 2006 q 1.6 10 19 := ni 10 10 := Vth 0.026 := ε 0 8.854 10 14 := ε s 11.7 ε 0 := ε ox 3.9 ε 0 := μ m 10 4 := nm 10 7 := mV 10 3 := μ _n 1450 := cm 2 /V-sec (1) (a) Is 10 14 := Id Vd ( ) Is exp Vd Vth 1 := Id 0.7 ( ) 4.927 10 3 × = r_d Vth Id 0.7 ( ) := r_d 5.278 = Ω (b) Nd 10 16 := Na 10 18 := Area 100 μ m 2 := φ n 60 mV log Nd ni := φ n 0.36 =

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