Homework1-sol - = (2 C + L W ) R = (2 0.65 + 150 3 )(806)...

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UNIVERSITY OF CALIFORNIA AT BERKELEY College of Engineering Dept. of Electrical Engineering and Computer Sciences Problem Set #1 Due Tuesday, January 31, 2006. EE 105 Spring 2006 1. a) electron b) n-type c) N d ' = N d ± N a = 1.1 ² 10 13 ± 1 ² 10 13 = 1 ² 10 12 cm ± 3 ³ n o = N d ' + N d ' 2 + 4 n i 2 2 = 10 12 + 10 24 + 4 ² 10 20 2 = 1.0001 ² 10 12 cm ± 3 ³ p o = n i 2 n o = 9.9999 ² 10 7 cm ± 3 2. a) n o ± N d = 2 ² 10 16 cm ³ 3 μ n ± 1050 cm 2 / Vs b) N d ± N a = 1 ² 10 16 cm ± 3 ³ N a = 1 ² 10 16 cm ± 3 (dopant type : acceptor) ³ n ´ 950 cm 2 / Vs 3. a) R ± = 1 qN d n t = 1 (1.6 ± 10 ² 19 )(10 17 )(775)(10 ² 4 ) ³ 806 ´ / ± b) R = NR
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Unformatted text preview: = (2 C + L W ) R = (2 0.65 + 150 3 )(806) 41.3 k c) R 1 = 1 qN d 1 n 1 t 1 1 (1.6 10 19 )(2 10 17 )(600)(0.25 10 4 ) 2.08 k / R 2 = 1 qN d 2 n 2 t 2 1 (1.6 10 19 )(10 17 )(775)(0.75 10 4 ) 1.08 k / R eq = R 1 // R 2 = (2.08 k 1 + 1.08 k 1 ) 1 710.89 /...
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