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Unformatted text preview:h= 3 k 2 , = 6 k . Since k= (3t ) 2 , = 2 (3t ) (3) = 18t . Substitute to find .=⋅ = 6 k ⋅ 18t = 108 ktNow subsitute (3 t )2 for k. = 108(3 t ) 2 t = 108 ⋅ 9 t 2 ⋅ t = 972 t 3 dhdt dh dkdk dtdh dk dkdt dhdt dh dtdh dkdk dt dhdt