10/27/19, 8
:
45 PM
Thinkwell  Exercise
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What is the area between the curve
y
=
x
2
+ 3 and
the
x

axis on the interval [1, 3]?
Correct!
You said B:
The correct answer is B:
Explanation:
Since you are given the limits of integration, the
first step to find the area is to set up the integral.
Then solve.
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A
= 14
2
3
A
= 14
2
3
A
=
∫
3
1
(
x
2
+ 3
)
dx
=
[
+ 3
x
]
3
1
=
[
+ 3(3)
]

[
+ 3(1)
]
= [9 + 9]

[
+ 3
]
= 18

3
= 14
x
3
3
(3)
3
3
(1)
3
3
1
3
1
3
2
3