Hw3Solutions - UNIVERSITY OF CALIFORNIA AT BERKELEY College...

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UNIVERSITY OF CALIFORNIA AT BERKELEY College of Engineering Dept. of Electrical Engineering and Computer Sciences Problem Set #3 Solutions Due Tuesday, February 14, 2006. EE 105 Spring 2006 1. a. The total negative charge (magnitude) is equal to the positive charge from the sheet charges and thus: (1000 + 1000)(10 -7 )(-2m) = 2Q Q = 200nC/cm 2 . b. Keep in mind that when an impulse function is integrated, it results in a step function about the location of the impulse function. So: Take a moment for a sanity check: while -3000nm<x<-1000nm, there is a positive charge to the left, and a net negative charge to the right; a positive test charge would go right, and hence the electric field has a positive (constant) value. At x=0nm, a positive test charge remains happy right in the middle (literally – it’s a point of stable equilibrium for a positive test charge, as the potential graph will later indicate), so E(0) had better be 0.
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