EECS
Hw7Solutions

# Hw7Solutions - UNIVERSITY OF CALIFORNIA AT BERKELEY College...

• Homework Help
• 1

This preview shows page 1. Sign up to view the full content.

UNIVERSITY OF CALIFORNIA AT BERKELEY College of Engineering Dept. of Electrical Engineering and Computer Sciences Problem Set #7 Due Tuesday, March 21 st , 2006. EE 105 Spring 2006 1) a. v out = R L R L + R out 10 v i and v i = R in R S + R in v in " v out = R L R L + R out R in R S + R in 10 v i " v out / v i = 10 R L R L + R out R in R S + R in = 2.5 V / V b. Remember that i out is defined as the small signal current entering the port, and thus the minus sign is needed above. i out / v in = " 10 R L + R out R in R S + R in = " 250 μ S c. i out = " 10 v i R L + R out = " 10 i in R in R L + R out # i out / i in = " 10 R
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: R in R L + R out = 50 mA / A d. v out = R L R L + R out 10 v i and v i = i in R in " v out / i in = 10 R in R L R L + R out = 500 # 2) a. I BIAS = " I SUP = " 100 A b. R in = 1/ gm = 1/( 2 n C ox ( W / L ) I D ) = 5.77 k " R out = r o (1 + gmR S )// r oc = r o ((1 + gmR S ) " 1 + 1) " 1 = ( # n I D ) " 1 ((1 + gmR S ) " 1 + 1) " 1 = 366 k \$ c. i out / i in = " R S R S + R in R out R L + R out = " 0.617 A / A 3) a. V BIAS = V Tn + 2 I SUP n C ox ( W / L ) = 1.59 V b. R in "# and R out = 1/ gm = 1/( 2 n C ox ( W / L ) I D ) = 2.24 k " c. " v out / v s = R L R L + R out = 42.8 mV / V...
View Full Document

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern