Chapter 2 - Q2 Pg 53 Question 3 a EF...

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Pg. 53 Question 3) a) EF = {(1,2), (1,4), (1,6), (2,1), (4,1), (6,1)} b) E U F = {If the sum of the die is odd OR at least one of the dice lands on 1} c) FG = {(1,4), (4,1)} d) EF c = {Neither of the dice lands on 1 and the sum of the die is odd} e) EFG = {(1,4), (4,1)}
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Pg. 54 Question 7) a) For each member of the team there are 3 political affiliations and 2 types of workers à 6 choices per team member. Therefore by the counting principle there are a total of 6 15 outcomes in the sample space. b) This is the same as Total # of Events – NONE of the team members is a Blue- collared Shirt. If NONE of the team members are Blue-Collared workers, then there are (3x1 = 3) choices per team member for a total of 3 15 choices. Therefore the number of events that at least one of the members is a blue- collared worker is: 6 15 - 3 15 c) Here the total number of possibilities for each team member are 2 Job types (Blue or White Collared) and 2 Political Affiliations (Democrat or Republican) à (2 x 2 = 4) 15 total outcomes.
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