CHE
22._Mar-7

# 22._Mar-7 - Combustion of Ethane L00 Lb — Ethane is...

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Unformatted text preview: 3/7/2008 Combustion of Ethane L00 Lb) — Ethane is burned with 509’ xcess air. The percentage conversion of the ethane is 90%; of the ethane burned, 2&6 reacts to form C0 and the balance reacts to form C352. Calculate the m’tﬂar composition (:57 of the star: 3 on a ry 3515 and the mole ratio of water to dry stack gas. I - pr -‘ _‘ ‘/_ m ﬂ _, 7.! 'IA’ 4 . M A 6 SOLD :m -r r M2; “mo 3 . / . {A Di' ' ’ ‘“ 1' _A-1).AO ’ .VI— ’4 a," la ._ —~"-'w VA- ‘A A A_l I'IIAAO .0 I" 1" v u a. ’l 5 . —/7 A ,. + 3 ‘ ~rxn® 7/ n ‘ '_ 3 l F‘Y‘I‘ '\ + ')_ I 6M]? 48 —3 prﬂ _ Combustion of a Hydrocarbon Fuel of Unknown Composition _ A hydrocarbon gas is burned with air. The dryrbasis product gas composition is 1.5 mole% CO, 6.0% _ — C02, 8.2% 02, and 84.3% N2. There is no atomic oxygen in the fuel. Calculate the ratio of hydrogen- _ to carbon in the fuel gas and speculate on what the fuel might be. Then calculate the percent exeess_ air fed to the reactor. nc(m0| C) —>* — nH(mo| H) ”amOI air) 100 mol dry gas — {121 mol o2/m0| 0.015 mol CO/mol dry gas 079 mol N2/m0| 0.060 mol CO2/mol dry gas 0.082 mol 02/mol dry gas 0.843 mol N2/mol dry gas nw(mo| H20) H + 01 —-9 (’0 +-——- H40 'W'M‘f’ “’"T ‘ la 4‘ A " ' (RH =5 2 M... w or m ' \V/J/ _ b 2 _ V at- (VOL na(mol air) 100 mol dry gas W 0.015 mol CO/mol dry gas 079 mol N2/mol 0.060 mol 002/mol dry gas 0.0§__g_mo| 02/m0| dry gas 0.843 mol N2/mol dry gas nw(m0| H20) ...
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