CHEM
Chemistry 1A - Fall 2006 - Pines - Midterm 1 Solutions

Chemistry 1A - Fall 2006 - Pines - Midterm 1 Solutions -...

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Page 1 KEY Chemistry 1A, Fall 2006 Midterm 1, Version A Sept 19, 2006 (90 min, closed book) Name:___________________ SID:_____________________ TA Name:________________ There are 24 Multiple choice questions worth 2.5 points each. There are 4, multi-part short answer questions. For the multiple choice section, fill in the Scantron form AND circle your answer on the exam. Put your final answers in the boxes provided. Full credit cannot be gained for answers outside the boxes provided. The homework and chemquizzes that each question is based upon is listed after the question e.g. [HW 1.13, CQ 7.3] Question Score Multiple Choice Section Question 25 Question 26 Question 27 Question 28 Total
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Page 2 Thermodynamics: G ° = H ° - T S ° H ° = Σ H ° f (products) - Σ H ° f (reactants) S ° = Σ S ° (products) - Σ S ° (reactants) G ° = Σ G ° f (products) - Σ G ° f (reactants) S = k B lnW S = q rev /T E = q + w w = - P ext V for aA + bB cC + dD b a d c B A D C Q ] [ ] [ ] [ ] [ = At equilibrium, Q = K G = G ° + RTln Q G = G° + RTln(a); a = activity = γ P/P° or γ [A]/[A]° G ° = - RTln K G ° = - nF Є º Є = Є º - (RT/nF) lnQ R S T R H K ° + ° = 1 ln T = ik b,f m Π = iMRT P total = P A + P B = X A P A ° + X B P B ° Acid Base: pH = - log[H 3 O + ] pX = - log X ] [ ] [ log HA A pK pH a + = Kinetics: [A] t = [A] 0 e -kt ln[A] t = ln[A] 0 – kt t 1/2 = ln2/k 1/[A] t = 1/[A] 0 + kt k = A e (-Ea/RT) ln(k 1 /k 2 ) = E a /R ( 1/T 2 – 1/T 1 ) t 1/2 = 1/[A] 0 k t 1/2 = [A] 0 /kt Quantum: E = h ν λν = c λ deBroglie = h / p = h / mv E kin (e-) = h ν - Φ = h ν - h ν 0 = R n Z E n 2 2 x p ~ h p = mv Particle in a box (1-D Quantum): E n = h 2 n 2 /8mL 2 ; n = 1, 2, 3... Vibrational: E v = (v + ½) hA/2 π ; A =(k/m) ½ Rotational: E n = n(n + 1) hB; B = h/8 π 2 I; I = 2mr 2 m = m A m B /(m A + m B ) Ideal Gas: PV = nRT RT E kin 2 3 = M 3RT v rms = Contants: N 0 = 6.02214 x 10 23 mol -1 R = 2.179874 x 10 -18 J R = 3.28984 x 10 15 Hz k = 1.38066 x 10 -23 J K -1 h = 6.62608 x 10 -34 J s m e = 9.101939 x 10 -31 kg c = 2.99792 x 10 8 m s -1 T (K) = T (C) + 273.15 F = 96,485 C / mol 1 V = 1 J / C Gas Constant: R = 8.31451 J K -1 mol -1 R = 8.20578 x 10 -2 L atm K -1 mol -1 1 nm = 10 -9 m 1 kJ = 1000 J 1 atm = 760 mm Hg = 760 torr 1 bar 1 L atm 100 J
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Page 3 M ULTIPLE C HOICE For questions 1-3, complete the following table by filling in the numbered boxes. If an entry cannot be determined from the information given and the information on your periodic table, enter CBD (cannot be determined). Atomic masses are given in amu to three significant figures. Provide symbols as shown, using CBD if the complete symbol cannot be determined.
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