HW3 Sol

HW3 Sol - go I 1 Q L.100 km owe Power 1‘20 k redfve...

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Unformatted text preview: go I 1/??? Q L} ) .100 km owe Power 1‘20 k redfve FoLbQV :9 Powek 2 01, 22:05 (arcw'MO/mfl: “5’3 W Policy -* fl; .190 />,eN/ :9 [OQJCv’QR Incremmed}/mn+k @ ’ $ Sfi/yeou'“ :9 3.00 KVAR LAC FQQIMM/WW4’h 470]" 1680 ‘— 100 w [30 renal-17 (0))"ftgl33- 72+“! conL 433; Lib Cl) 2% _ 4,30 a .30 :0 :9 pawl», [37; $0 (“2% 39:33) Eh, (95%1$33§ Pol¥CjCD i5 128%“? 0’5) ‘40 “VL‘LQLO - 0440" :2) Vi: FJ‘ 190K xOfilxle‘J age/£90" 1/ Wu; v6?) = )16- cos“ (loofl'fi‘ + ‘20") 1/ VOW 7 .103} (ZOOK'JIL “ \/ A1211: Vol/‘1' :—-VJ_ J 1L _H {O 1, : Ar 3 outf— {Lb—VI) 4)l/H/I\/[O (pg VI 2': “ML! I V [.0- , #PLVwa—FfloMK Q? —~\/ou-+ ) r #)le140 )Wl—l —)L)M V‘ “E L!- Ir cf {0 \/UL+"I f )wH [LO ' L). 0 LP /_{_ UJrh :O (beat/11,2 +118??? I; ha “Jeremdfik‘i' Sob‘rge Q7) (a) The input to the left of the unit will have the shape: / \ ' 3:; x a n- \ \ -fl.2- {L4- \ as — \ / .u'.a - \ /f -1 n 1 2 t [SJ and the output voltage will he: 2:: / 332/ / if; I I I I ITS) We need to reduce the magnitude from 115-\-" (rms) to a peak voltage of 5 V". The corresponding peak voltage at the input will be 11535: 162.6 Y. so we require a transformer with a turns ratio of 162.6:5 or about 32.5:1. connected as shown: 1:6 . 115v I. I'lllS [1C a = 1532.5 (b) If we wish to reduce the "'ripple" in the output voltage. we can connect a capacitoi‘ in parallel with the output terminals. The necessary size will depend on the 111axi111urn allowable ripple voltage and the 111inirnum anticipated load resistance. When the input voltage swings negative and the output voltage tries to reduce to follow. current will flow out of the capacitor to reduce the amount of voltage drop that would otherwise occur. ...
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