{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

HW4 Sol - Qt S‘f fl(3;2HMH7 634553 d My(3 l g/S wrww ...

Info icon This preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Qt S‘f fl (3+;2HMH7) : 634553 d _ My} (3 l g/S ? §+wrww §* “Mm / /f§*+3>.§—HY :9 €“fi9uglfl:failfi (617515 Y g”: / j : Ma): 75 yaw) 6%hwfl)af3 M #54—frw’q§%flmé*“* ) 1. H HG) :gijé @e- K :1 Hwy Jrflr. g? raw/L; St? L. :17 W) =— [LA 359) +4 ( gar) “ire—"Jr 516* 7' r” -—- e Q3.) (9; f} - 3m 3} mad-1:5 4 I “H CH4 "KS"?! , (13) a) 45 «Q mg): #0») : ghbm i“ 1W): 1“ 3135,31 A, O 5?” §L—é$+{9 F 7; JD) {ildl W @1315 “0‘ SR5) 1 5"“ fiéHzo {$1 _ 51 :0 4553-015 5 fl” § Fa) : /O_£J'L 40.0095+m0 J1 13; ML, - -6 £91 “768% :. £6312 +£{WW_ /62.65 S S1_{_%fll 523' V6.13 #31“ V(;) ’75—; (5L+ l-OQLFXJOS x '21- N _ ’7—(f (SL4 [ch )qogiqt» L250 (5+ 510%?)(54r3m1/g # 341.3337 {shz’zflfl +7.??fi4X/o? q )9 c 6‘ :— —-*”“' + If!“ Jr (“ms—y (943%) (Sam) +[52h-Jhx) B) we marl/«74 0‘0 m‘éue’: 0k: 4! .8 J a) #66. n J c : 0.11% M15?” (7“: 0413329 kz’S’V/t Jim-t c VGU : #3:.9 51mm H5518 +. 3.354 (05(1sz MN!) MW in T16 yifgokd/ w grade Volfige marog Hm (wacf'for' K V I [259% Co; (1va fgy-9/°)jm\/ TIM; (M be erHeyx M Phafior nohh‘on at) 0.11641439/‘31/ 5—“— OMIHQAWflWX {4 [1? 44?,9/ “A #4 km a $43 11 S gm 3% x 12m 2 7.12)? (of QM) A C) PhM‘ok andyg‘gj bye com (Age EFMPR voHofle Amigo“ (To (fwd Hag Velmge dryimn +0 4):\AC‘l/\Vol—lfirgf C (1‘ {)mC- (“for (/6245: )( 0,03lfiyl; 4?}. 57V) Vccm : “w : 0,15fl/4f1’ir 2g + 0.0314; 4%?- 9/9 TLW I'S Hm: {7‘2an fade {egfmfé CURL-L e} +L£ fame WM] 0*) man/oer , VCU“) #:d 3: FodVCf'. 3 1).? C05C2K7F gage > LOLNZF ES. +Ifl€ game voIJrl/l amwer Q6) . . . . 5 ' We begm by shorting the 7 cos 41‘ source. and replacing the 5 cos 2? source With 5 s2 + 4 I (3) Define four clockwise mesh currents 1]. lg. 13 and ]x in the top left. top right. bottom left and bottom right meshes. respectively. Then. 55 2 = (12 +1.-'2s)1_s —3 1l —(1.-' 2s)1x [1] 5 +4 0 =-41.+(9.5+s)11—s13—31_. [2] 0 = (3——s+2..-'s)13—s11—31. [3] 0 = (4 —— 3s+ 1_.-"2s) 1x _ 312 —(l_.-"2s) 13 [4] W = (I; —ls) (2s) [5.] Solving all five equations simultaneously using MATLAB. we find that ‘__,,_ 2(ls3[?553 + 100.52 + 1325 + 152] 1 1212s6 + 3311s5 + 2825.54 + 1528053 + 12411143;2 +1111485 +1201) Ts s2 +16- Define four clockwise mesh currents I]. [3. 13 and IM in the bottom left. top left. top right and bottom right meshes. respectit—‘el‘;r (note order Changedfl'om above). Then. Next we short the 5 cos 21‘ source. and replace the '1' cos 41‘ source with U=112+1.525;]ll—T’lg—[l..-"2slllx [I] 0=—41,.+10.5+s112—s13—?11 [2] — 275 =13+s+2..-'s11_.—s13—31. [3] 5 +16 0 = 14+3s+ l_.-"2s] 1x—3 13—11331 1] [4] vi” = 111—1311231 [5] Solving all five equations simultaneously using MATLAB. we find that .3! 51515332215.2 -Ss- 111) 1T1 — {"121235'5 + 331135 +22420s‘1 + 555135;3 + 48'1'3ICIs2 +40590s +4800] The next step is to form the sum \-"[(5) = + V1”. which is accomplished in MATLAB using the function sjy'umdfl J: V 1 = symadclfl" l prime. 1\1-'ldoubleprime): ‘1“) _ lils.3(815»5+110'1"s4 +73133‘3 +1'1"130s2 +21180~s+ 12160) '1. . . . {‘52 + 4111121256 + 3311s5 + 2242054 + 55513s3 + 48230.52 + 405905 + 4800} (b) Using the Hapfaed) routine from MATLAB. we find that 1.410 = [0.21573 501+ 6.903x10-3 cos 21— 2.403 sin 21— 0.116? ism-"1‘ — 0.1943 sot-“5’ cos 0.903: + 0.1611 set-3”“ sin 0.903: — 0.823x10'3 s-“-'-"“‘ + 3.229 cos 41+ 3.626 sin 4!] 31(1) V ...
View Full Document

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern