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**Unformatted text preview: **t = [t1,t2,t3,t4]; % total time interval x = [x1,x2,x3,x4]; % total signal plot(t,x) Problem 3.2.1 (a,b,c)(ii): a) (s – 3) 2 + 25 = (s – 3) (s – 3) + 25 = s 2 – 6s + 9 + 25 Therefore, standard second-order form is: s 2 – 6s + 34 ω n 2 = 34 Therefore: ω n = 34 = 5.83 Then it follows that 2ζω n = -6 Therefore: ζ = 34 2 6-= - 0.5144 b) Vector and Command: P = [1 -6 34]; damp(P); Damping (ζ) = -5.14e-001 Freq. (rad/s, ω n ) = 5.83e+000 Eigenvalue = 3.00e+000 + 5.00e+000i & 3.00e+000 - 5.00e+000i c)...

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- Spring '08
- DJStilwell
- matlab, Signal 1, Signal 2, Christopher Belcastro, interval % signal