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Unformatted text preview: Where in part (I) we found the initial velocity. Solving Eq.2-10c for acceleration and plugging in we get The negative sign means the acceleration is upwards which decelerates the person. Solution (b) We see from Eq. 2-10c (1 of 2) [1/31/2008 12:18:18 PM] A larger net stretch ( ) gives a smaller deceleration. So the net should be (2 of 2) [1/31/2008 12:18:18 PM]...
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- Acceleration, Velocity, larger net stretch