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**Unformatted text preview: **Where in part (I) we found the initial velocity. Solving Eq.2-10c for acceleration and plugging in we get The negative sign means the acceleration is upwards which decelerates the person. Solution (b) We see from Eq. 2-10c http://www.hwproblems.com/cgi-bin/book.cgi?bookid=0044&cptn=2pr57&id=62762 (1 of 2) [1/31/2008 12:18:18 PM] http://www.hwproblems.com/cgi-bin/book.cgi?bookid=0044&cptn=2pr57&id=62762 A larger net stretch ( ) gives a smaller deceleration. So the net should be http://www.hwproblems.com/cgi-bin/book.cgi?bookid=0044&cptn=2pr57&id=62762 (2 of 2) [1/31/2008 12:18:18 PM]...

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