chp2 problem67 soln

# Physics: Principles with Applications

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Chapter2 problem 67 In each case we use a coordinate system with the origin at the beginning of the putt and the positive direction in the direction of the putt. The limits on the putting distance are 6.0 m < x < 8.0 m. For the downhill putt we have: v 2 = v 0down 2 + 2 a down( x x 0); 0 = v 0down 2 + 2(– 2.0 m/s2) x . When we use the limits for x , we get 4.9 m/s <
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Unformatted text preview: v 0down < 5.7 m/s, or D v 0down = 0.8 m/ s . For the uphill putt we have: v 2 = v 0up 2 + 2 a up( x – x 0); 0 = v 0up 2 + 2(– 3.0 m/s2) x . When we use the limits for x , we get 6.0 m/s < v 0up < 6.9 m/s, or D v 0up = 0.9 m/s . The smaller spread in allowable initial velocities makes the downhill putt more difficult....
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