Math 192 Final Cheatsheet

# Math 192 Final Cheatsheet - Vector perpendicular to plane v...

• Notes
• 1

This preview shows page 1. Sign up to view the full content.

Vector perpendicular to plane, v PQ PR = r uuur uuu v ; Area = (1/2) PQ PR P uuur uuur . Parallelepiped = ( ) A B C P Plane through P orthogonal to u , replace i , j , k , with x, y, and z, respectively. It is equal to the plane equation with a point (like P) inserted. Equation of line through P and Q P PQ P PQ p PQ x x t x y y t y z z t z P P = + = + = + uuur uuur uuur (where x PQ is the coefficient of x…; also where x p is the x-coordinate of point P) Distance PS n d n P = uuur r uur , where n is unit normal vector to plane. Projection PQ PS PQ proj PS PQ PQ PQ P = uuur uuur uuur uuur uuur uuur uuur Write PS as sum of a vector perpendicular to PQ and vector parallel to PQ Projection of PS over PQ (which is v-parallel) and (PS - v-parallel) [which is v-perpendicular]. Motion of Particle in Space
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Unit Tangent Vector ( ) ( ) v t v t r r . Arc Length ( ) t t v t dt P r Multivariable functions and partial derivatives Vector-Valued functions- ( ) ( ) ( ) ( ) F t f t i g t j h t k = + + r r r Domain : set of points (x,y,z) in which f is well defined Range : set of values of f . Level curves : set f(x,y) = function equal to constant (ex.: 3 = x 2 + y 4 ). Same for level curves, except with 3-variables. Limits : Remember to substitute y = mx, or y = mx+b (under y = mx+b form), or y = mx n to find whether limit does not exist. Linearization : ( , ) ( , )( ) ( , )( ) x y L f x y f x y x x f x y y y = +-+-...
View Full Document

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern